Fleurus_Island

Fleurus Island

Fleurus Island

Island in Graham Land, Antarctica


Fleurus Island is an island lying 1 km (0.5 nmi) south of Delaite Island in Wilhelmina Bay, off the west coast of Graham Land, Antarctica. it was shown on an Argentine government chart of 1950, and was named by the UK Antarctic Place-Names Committee in 1956 after the British ship Fleurus, which visited the area in 1928.[1]

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References

  1. "Fleurus Island". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved 27 March 2012.

Public Domain This article incorporates public domain material from "Fleurus Island". Geographic Names Information System. United States Geological Survey.



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