1896_United_States_presidential_election_in_Washington_(state)

1896 United States presidential election in Washington (state)

1896 United States presidential election in Washington (state)

Election in Washington


The 1896 United States presidential election in Washington took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. State voters chose four electors to the Electoral College, which selected the president and vice president.

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Washington was won by the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate Arthur Sewall of Maine. Two electors cast their vice presidential ballots for Bryan's Populist running mate Thomas E. Watson. They defeated the Republican nominees, former Governor of Ohio William McKinley and his running mate Garret Hobart of New Jersey. Bryan won the state by a margin of 15.13%,

As a result of his win in the state, Bryan would become the first Democratic presidential candidate to win Washington state. He would later lose the state against McKinley in 1900 and then against William Howard Taft in 1908. The state would not vote Democratic again until 1916.

This is the last time the losing candidate won a majority of Clallam County votes.

Results

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Results by county

More information County, William Jennings Bryan ...

See also

Notes


    References

    1. Robinson, Edgar Eugene; The Presidential Vote 1896-1932, pp. 364-367 ISBN 9780804716963
    2. Géoelections; Popular Vote at the Presidential Election for 1896 (.xlsx file for €30 including full minor party figures)

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