The 1884 United States presidential election in West Virginia took place on November 4, 1884, as part of the 1884 United States presidential election. West Virginia voters chose six representatives, or electors, to the Electoral College, who voted for president and vice president.^[2]

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1884 United States presidential election in West Virginia

← 1880 November 4, 1884 1888 →
Turnout	21.37% of the total population 3.16 pp[1]
Nominee Grover Cleveland James G. Blaine Party Democratic Republican Home state New York Maine Running mate Thomas A. Hendricks John A. Logan Electoral vote 6 0 Popular vote 67,311 63,096 Percentage 50.94% 47.75%
County Results Cleveland   40-50%   50-60%   60-70%   70-80%   80-90% Blaine   40-50%   50-60%   60-70%   70-80%
President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

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West Virginia was won by Grover Cleveland, the 28th governor of New York, (D–New York), running with the former governor of Indiana Thomas A. Hendricks, with 50.94 percent of the popular vote, against Secretary of State James G. Blaine (R-Maine), running with Senator John A. Logan, with 47.75 percent of the vote.^[2]

The Prohibition Party chose John St. John, the former governor of Kansas, and former Maryland State Senator William Daniel as their presidential and vice-presidential candidates and received 0.71 percent of the vote. The Greenback and Anti-Monopoly Parties both chose major general and former governor of Massachusetts Benjamin Butler and Absolom M. West, an unseated Mississippi representative, received 0.60 percent of the vote.

This would prove the last time the Democratic Party won an absolute majority of West Virginia’s popular vote until 1932.