1880_United_States_presidential_election_in_Delaware

1880 United States presidential election in Delaware

1880 United States presidential election in Delaware

Election in Delaware

The 1880 United States presidential election in Delaware took place on November 2, 1880, as part of the 1880 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

Main article: 1880 United States presidential election
Quick Facts Nominee, Party ...

Delaware was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 51.53% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 48.03% of the vote.[1]

As of 2023, this is the most recent time that a Republican won the presidency without carrying Sussex County.

Results

More information Party, Candidate ...

See also

References

  1. [1]
    "1880 Presidential Election Results Delaware".


Stub icon 1 Stub icon 2

This Delaware elections-related article is a stub. You can help Wikipedia by expanding it.
Share this article:

This article uses material from the Wikipedia article 1880_United_States_presidential_election_in_Delaware, and is written by contributors. Text is available under a CC BY-SA 4.0 International License; additional terms may apply. Images, videos and audio are available under their respective licenses.