1860_United_States_presidential_election_in_Vermont

1860 United States presidential election in Vermont

1860 United States presidential election in Vermont

Election in Vermont

The 1860 United States presidential election in Vermont took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose five electors of the Electoral College, who voted for president and vice president.

Main article: 1860 United States presidential election
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Vermont was won by Republican candidate Abraham Lincoln and his running mate Hannibal Hamlin They defeated Democratic candidate Stephen A. Douglas and his running mate Herschel V. Johnson. Lincoln won the state by a landslide margin of 56.45%.

With 75.86% of the popular vote, Vermont would be Lincoln's strongest victory in terms of percentage in the popular vote.[1]

Stephen A. Douglas was born in Brandon, Vermont.

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See also

References

  1. [1]
    "1860 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. [2]
    "1860 Presidential General Election Results - Vermont".


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