The 1836 United States presidential election in Arkansas took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

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1836 United States presidential election in Arkansas

November 3 – December 7, 1836 1840 →

Nominee Martin Van Buren Hugh White Party Democratic Whig Home state New York Tennessee Running mate Richard Johnson John Tyler Electoral vote 3 0 Popular vote 2,380 1,334 Percentage 64.08% 35.92%

County Results Van Buren   50-60%   60-70%   70-80%   80-90%   90-100% White   50-60%   60-70% No Vote:

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

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Arkansas, having been admitted to the Union as the 25th state on June 15, 1836, voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White during its first presidential election. Van Buren won Arkansas by a margin of 28.16%.

• United States presidential elections in Arkansas