1958_U.S._National_Championships_–_Women's_singles

1958 U.S. National Championships – Women's singles

1958 U.S. National Championships – Women's singles

1958 tennis event results


Defending champion Althea Gibson defeated Darlene Hard in the final, 3–6, 6–1, 6–2 to win the women's singles tennis title at the 1958 U.S. National Championships.[1]

Quick Facts Women's singles, Final ...

Seeds

The seeded players are listed below. Althea Gibson is the champion; others show in brackets the round in which they were eliminated.[2]

  1. United States Althea Gibson (champion)
  2. United States Dorothy Knode (quarterfinals)
  3. United Kingdom Ann Haydon (third round)
  4. Brazil Maria Bueno (quarterfinals)
  5. United States Janet Hopps (first round)
  6. United States Sally Moore (quarterfinals)
  7. United Kingdom Christine Truman (quarterfinals)
  8. United States Beverly Baker Fleitz (semifinals)

Draw

Key

Final eight

Quarterfinals Semifinals Finals
               
1 United States Althea Gibson 11 6
7 United Kingdom Christine Truman 9 1
1 United States Althea Gibson 6 6
8 United States Beverly Baker Fleitz 4 2
4 Brazil Maria Bueno 1 2
8 United States Beverly Baker Fleitz 6 6
1 United States Althea Gibson 3 6 6
United States Darlene Hard 6 1 2
4 United States Dorothy Knode 3 2
United States Jeanne Arth 6 6
United States Jeanne Arth 5 2
4 United States Darlene Hard 7 6
4 United States Darlene Hard 6 6
6 United States Sally Moore 4 3

References

  1. Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 471. ISBN 978-0942257700.
  2. "Aussie Tennismen Head Seedings for National Singles". The Terre Haute Star. AP. August 27, 1958. p. 12.
Preceded by Grand Slam women's singles Succeeded by

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