1955_Wimbledon_Championships_–_Girls'_singles

1955 Wimbledon Championships – Girls' singles

1955 Wimbledon Championships – Girls' singles

1955 tennis event results

Sheila Armstrong defeated Béatrice de Chambure in the final, 6–2, 6–4 to win the girls' singles tennis title at the 1955 Wimbledon Championships.[1]

Quick Facts Girls' singles, Final ...
Main article: 1955 Wimbledon Championships

Draw

Key

Draw

First round Quarterfinals Semifinals Final
Denmark T Dahl 0 3
Australia W Middleton 6 6
Australia W Middleton 4 4
France Béatrice de Chambure 6 6 France Béatrice de Chambure 6 6
Republic of Ireland Gene Hogan 0 0 France Béatrice de Chambure 6 6
West Germany G Stelges 4 10 3 Netherlands Fredy Marinkelle 0 1
Netherlands Fredy Marinkelle 6 8 6 France Béatrice de Chambure 2 4
United Kingdom Sheila Armstrong 6 6 United Kingdom Sheila Armstrong 6 6
Norway B Lorentzen 0 1 United Kingdom Sheila Armstrong 6 7
Jamaica D Crampton 7 2 Belgium MN Fossion 1 5
Belgium MN Fossion 9 6 United Kingdom Sheila Armstrong 6 6
South Africa Valerie Koortzen 3 2
South Africa Valerie Koortzen 6 6
Sweden L Engdahl 0 2

References

  1. [1]
    "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
Share this article:

This article uses material from the Wikipedia article 1955_Wimbledon_Championships_–_Girls'_singles, and is written by contributors. Text is available under a CC BY-SA 4.0 International License; additional terms may apply. Images, videos and audio are available under their respective licenses.