1788-89_United_States_presidential_election_in_Connecticut

1788–89 United States presidential election in Connecticut

1788–89 United States presidential election in Connecticut

Election in Connecticut

The 1788–89 United States presidential election in Connecticut took place on January 7, 1789 as part of the 1789 United States presidential election. The state legislature chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.[1]

Main article: 1788–89 United States presidential election
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Connecticut, which had become the 5th state on January 9, 1788, unanimously cast its seven electoral votes for George Washington during its first presidential election.

Electors

Samuel Huntington, Richard Law, Matthew Griswold, Erastus Wolcott, Thaddeus Burr, Jedediah Huntington, and Oliver Wolcott served as electors.[2]

See also

References

  1. [1]
    "The Electoral Count for the Presidential Election of 1789". The Papers of George Washington. Archived from the original on September 14, 2013. Retrieved May 4, 2005.
  2. [2]
    Jensen & Becker 1976, p. xxvii.

Works cited


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